본문으로 바로가기
728x90
반응형

문제

 

 

반응형

풀이

 

 

 

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
class Solution {
    public int solution(int number, int limit, int power) {
        int answer = 1;                             //1의 약수의 개수 1개
        for(int i=2; i<=number; i++) {              //2부터 number 까지
            int count = 2;                          //2부터는 무조건 약수의 개수가 2 이상이므로
            for(int j=2; j<=Math.sqrt(i); j++) {    //약수의 개수 구하는 for문
                if(i % j == 0) {
                    if(j == Math.sqrt(i)) {
                        count++;
                    }else {
                        count += 2;
                    }
                }
            }
            if (count > limit) {                    
                answer += power;
            } else {
                answer += count;
            }
        }
        return answer;
    }
}
cs

 

728x90
반응형